1 hr 28 min 45 s - 45 min 12 s equals?

Answer 1

To calculate (1 , \text{hr} , 28 , \text{min} , 45 , \text{s} - 45 , \text{min} , 12 , \text{s}), first convert everything to seconds: (1 , \text{hr} = 3600 , \text{s}), so (1 , \text{hr} , 28 , \text{min} , 45 , \text{s} = 3600 + 1680 + 45 = 5325 , \text{s}). Then convert (45 , \text{min} , 12 , \text{s}) to seconds: (45 , \text{min} = 2700 , \text{s}), so (45 , \text{min} , 12 , \text{s} = 2712 , \text{s}). Subtracting gives (5325 , \text{s} - 2712 , \text{s} = 2613 , \text{s}), which converts back to (43 , \text{min} , 33 , \text{s}).