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1+4/y = 12/y2

Multiply all terms by y2 to eradicate the denominators of the fractions:

y2+4y = 12

Bring 12 over to the LHS which changes to -12, you now have a quadratic equation to solve:

y2+4y-12 = 0

Solve the equation by factorising:

(y-2)(y+6) = 0

Therefore: y = 2 or y = - 6

By substituting either values into the original equation: 3 = 3 or 1/3 = 1/3

When substituting note that - 62 = 36

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Q: 1 plus 4 over y equals 12 over y squared?
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