1+4/y = 12/y2
Multiply all terms by y2 to eradicate the denominators of the fractions:
y2+4y = 12
Bring 12 over to the LHS which changes to -12, you now have a quadratic equation to solve:
y2+4y-12 = 0
Solve the equation by factorising:
(y-2)(y+6) = 0
Therefore: y = 2 or y = - 6
By substituting either values into the original equation: 3 = 3 or 1/3 = 1/3
When substituting note that - 62 = 36
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b = sqrt32 or 4 root 2
92
It also equals 13 12.
1 over 3 plus 1 over 12 equals 5 over 12
(x - 6)(x - 2)