1+4/y = 12/y2
Multiply all terms by y2 to eradicate the denominators of the fractions:
y2+4y = 12
Bring 12 over to the LHS which changes to -12, you now have a quadratic equation to solve:
y2+4y-12 = 0
Solve the equation by factorising:
(y-2)(y+6) = 0
Therefore: y = 2 or y = - 6
By substituting either values into the original equation: 3 = 3 or 1/3 = 1/3
When substituting note that - 62 = 36
b = sqrt32 or 4 root 2
92
It also equals 13 12.
1 over 3 plus 1 over 12 equals 5 over 12
X=-3
X = √63
b = sqrt32 or 4 root 2
92
If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108
It also equals 13 12.
12 squared plus 18 squared is equal to 468.
1 over 3 plus 1 over 12 equals 5 over 12
this is a pythagorean triple and c2=169 so c=13 25+144=169=132
X=-3
(x - 6)(x - 2)
92 = 81122 = 14481 + b2 = 144(take 81 from both sides)b2 = 63b = 7.937253933
It is a quadratic equation in X, with two real roots.