There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
A rule, based on a polynomial of order 4 is:U(n) = (121n^4 - 1478n^3 + 6275n^2 - 2830n + 6312)/24 for n = 1, 2, 3, ...
what are the next 2 numbers in this sequence: 20 , 1 ,18 ,4 ,9 ,1
There is no problem with that sequence.
The lucas numbers are a sequence of numbers. They go as 1, 3, 4, 7, 11, 18 etc the sequence is bery similar to the Fibonacci sequence (1, 1, 2, 3, 5, 8, 13)
183 + 1 = 44 + 2 = 66 + 3 = 99 + 4 = 13Etc. The next number in the sequence would be 18, then 25, and so on.Ans 2.The previous answer contains an error.The next number in the sequence would be 18 (13 + 5),after which comes 24 (18 + 6 ) not 25.
3 4 6 9 13 18...1....2....3....4......5
6 and 10
Dart Board
5
18
The Greatest Common Factor of 18, 13, and 20 is 1.
what are the next 2 numbers in this sequence: 20 , 1 ,18 ,4 ,9 ,1
25 is the next number that appears in that sequence.
possibly 16
The next number in the sequence is 6. The numbers represent the scores travelling around a regular dartboard, clockwise from the top.
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
There is no problem with that sequence.
1 3 5 8 20 18 10