18,23,28,33,...
#1 is 18
#2 is 23
A difference of '5'
Hence we can write '5n + x = 18
Where 'n' equals '1'
Hence 5(1) + x = 18
5 + x = 18
Hence x = 18 - 5 = 13
So nth term is 5n + 13
NB Verification; does it work for the 4th term
5(4)+ 13 =
20 + 13 = 33
Which is true from above list.
The median is 19.
23
The variance is: 34.2678571429
what i have is mean is 22.2,median which is the middle is 23,range is 26, and mode is 12
Since there are 2 outcomes for a coin toss, and you will toss the coin 3 times the number of outcomes are 23 or 8. Since H-T-H can occur only 1 way, the probability of the H-T-H sequence is 1/8.
58
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
All you have to do is add 5 each time(x+5) It's 43
It is: 27-2n
It is T(n) = n2 + 4*n + 2.
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
Un = 5n - 2
It is: 5n+3 and so the next term is 28
5, 11, 17, 23, 29
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d