This means that 2y - 3 = 2y + 4 which is not possible.
4y + 4 = 2y + 12Subtract 2y from each side of the equation:2y + 4 = 12Subtract 4 from each side:2y = 8Divide each side by 2:y = 4
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
This means that 2y - 3 = 2y + 4 which is not possible.
4y + 4 = 2y + 12Subtract 2y from each side of the equation:2y + 4 = 12Subtract 4 from each side:2y = 8Divide each side by 2:y = 4
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
Exactly (2y + 4) .
2y = 5x + 8Divide each side by 2:y = 2.5x + 4The slope of the graph is 2.5 .The y-intercept is 4.
When y=4, x=8/5
x=4 y=0
parallel