The sequence seems to be calculated by f(n) = 3n + 2.3(1) + 2 = 5, 3(2) + 2 = 8, 3(3) + 2 = 11, and so on.Therefore, the 99th term would be 3(99) + 2 = 299
'11' The sequence is 'add 2' , the subtrtact '2'
The answer is 47 The first term has 3 added to it = 2 + 3 =5 The second term has 6 added to it = 5 + (3 x 2) =5 + 6 = 11 The 3rd term is = 11 + (6 x 2) = 11 + 12= 23 Hence the next one is = 23 + (12 x 2) = 23 + 24 = 47
26073.
Add 5 to form the next number in the sequence, then subtract 2 . . . repeat. 0 + 5 = 5 5 - 2 = 3 3 + 5 = 8 8 - 2 = 6 . . . and the series continues :- 6 + 5 = 11 11 - 2 = 9 . . . and so on
While there are not enough numbers to fully establish the sequence, the difference could be increasing by 3 each time, therefore, the sequence will go: 2, 5, 11, 20, 32... Or, the differences could be doubling each time, meaning that the sequence will go: 2, 5, 11, 23, 47...
While there are not enough numbers to fully establish the sequence, the difference could be increasing by 3 each time, therefore, the sequence will go: 2, 5, 11, 20, 32... Or, the differences could be doubling each time, meaning that the sequence will go: 2, 5, 11, 23, 47...
The sequence seems to be calculated by f(n) = 3n + 2.3(1) + 2 = 5, 3(2) + 2 = 8, 3(3) + 2 = 11, and so on.Therefore, the 99th term would be 3(99) + 2 = 299
'11' The sequence is 'add 2' , the subtrtact '2'
Sequence is +4 - 3 + 5 - 2 + 6 - 1 (+1 - 1)2 6 3 8 6 12 next number 11
The answer is 47 The first term has 3 added to it = 2 + 3 =5 The second term has 6 added to it = 5 + (3 x 2) =5 + 6 = 11 The 3rd term is = 11 + (6 x 2) = 11 + 12= 23 Hence the next one is = 23 + (12 x 2) = 23 + 24 = 47
23
It is a sequence, and it is...Start with two and add 3.
26073.
Add 5 to form the next number in the sequence, then subtract 2 . . . repeat. 0 + 5 = 5 5 - 2 = 3 3 + 5 = 8 8 - 2 = 6 . . . and the series continues :- 6 + 5 = 11 11 - 2 = 9 . . . and so on
17, it's the sequence of primes.
2 ,5, 11, 23, 47, 95 ....... Double up each time: 3, 6, 12, 24, 48 ........