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What is the missing number in sequence 2 - 5 - 14 - - 122?
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
What number is missing out of 2- 5- 14-122?
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
What is the missing number 2 2 6 2 14 2 30 2 ...2?
2
Find 3 consecutive natural numbers so that 3 times the 1st plus 4 times the 2nd plus 5 times the 3rd equals 122 what is the algebraic expression for that?
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True
What is the missing number 2 2 6 2 14 2 30 2 2?
2+2=
2 5 14 122 what is the missing sequence number?
41 should be in between 14 and 122
Missing number 2 5 14 122?
41.
What is the missing number in sequence 2 - 5 - 14 - - 122?
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
What number is missing out of 2- 5- 14-122?
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Find the missing number 14 9 12 12 10 15 8 18 6 21 24?
13168? hmm too short to know for sure. But there is a pattern I found. For the first number the difference from 2 and 0 is 2. So you times the difference by 2 (the number) and then add 1 to get 5. For the second number the difference from 5 and 2 is 3. So you times 3 (the difference) by 5 the number and then subtract 1 to get 14. For the third number the difference from 14 and 5 is 9. So 9 times 14 and then you subtract 4 to get 122. So, for the next number you would take the difference from 122 and 14 which is 108, then times that by 122 and get 13176, then following the pattern of (1, -1, -4) you would subtract 13176 by 8 to get 13168.
What number is next in this series 2 5 14 41 122?
365.
What is the missing number in this series 8 2 14 6 11 14 6 18 12?
Find the missing number in the series (in red) :2 , 4 , 5, 9, 9 , 16 , 14 , ? , 20 , ….
What number comes next. 2 5 14 41 122?
The next number works out as 365
What is the missing number 2 2 6 2 14 2 30 2 ...2?
2
Find 3 consecutive natural numbers so that 3 times the 1st plus 4 times the 2nd plus 5 times the 3rd equals 122 what is the algebraic expression for that?
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True
What is the missing number of 2 2 6 2 14 2 30 2 2?
62
Find the missing number 2 5 14 -- 122?
2,5,14 - - 122 Difference between 5 & 2 = 3 = 3^(1) Difference between 14 & 5 = 9 = 3^(2) This leads one to suppose the next difference will be 3^(3) = 27 Hence 14 + 27 = 41 Similarly the next difference again will 3^(4) = 81 Hence 41 + 81 = 122 As required. So the sequence is 2,5,14,41,122. NB The next difference again is 3^(5) = 243 Hence 122 + 243 = 365 is the next term in the sequence. =
