2/9 + 2/3 = 2/9 + 6/9 = 8/9
2 and 7 2+7=9 3,3, and 3 3+3+3=9 1,2,3, and 3 1+2+3+3= 9
Multiply the integer part with the denominator and add that to the numerator. For example: 3 2/3=? ↓↓ ↓↓ 3 * 3=9 ↓↓ 2 + 9=11 3 2/3=11/3 Or, if you like it cleaner: 3 2/3=? (3*3+2)/3=(9+2)/3=11/3
12
a+b = ab = 9 so a(9-a) = 9 = -(a-9/2)^2 +81/4 so a-9/2 = sqrt(45/4) = +- 3/2 sqrt(5) Therefore the two numbers are (9 + 3 sqrt(5))/2 and (9 - 3 sqrt(5))/2
2/9 + 2/3 = 2/9 + 6/9 = 8/9
2 and 7 2+7=9 3,3, and 3 3+3+3=9 1,2,3, and 3 1+2+3+3= 9
8/9 + 3/9 + 2/9 = 13/9 = 1 4/9
seven add 2 each time 3 + 2 = 5 5 + 2 = 7 7 + 2 = 9 3 5 7 9
Add 3, add 9, add 27, add 81 Adding successive powers of 3.
2/9 + 1/3 = 2/9 + 3/9 - Note the equivalence of the fraction 1/3 & 3/9 Add the numerators 5/9 The Answer . 5/9 = 0.555.... ( recurring to infinity as a decimal).
There are no two real numbers that will add to -9 and multiply to 81. Using complex numbers, the two numbers are: (-9/2 + i9/2√3) and (-9/2 - i9/2√3)
Multiply the integer part with the denominator and add that to the numerator. For example: 3 2/3=? ↓↓ ↓↓ 3 * 3=9 ↓↓ 2 + 9=11 3 2/3=11/3 Or, if you like it cleaner: 3 2/3=? (3*3+2)/3=(9+2)/3=11/3
18. you add 1, then 2, then 3 and so on.
12
It would be 6. The pattern is -divide by 2 add 2 add 3- repeat.
Change to common denominator 1/3 + 2/9 = 3/9 + 2/9 Add the numerators 3 + 2 = 5 Place the sum (5) over the common denominator (9). 5/9 is the answer.