The numbers are: 9 and -6
9
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
All you do is add all of the numbers 3 times and 1 an 9 4 times
-45
That is the way that it comes out.
9 and 6 but subtract not add
The numbers are: 9 and -6
9
There are no two real numbers that will add to -9 and multiply to 81. Using complex numbers, the two numbers are: (-9/2 + i9/2√3) and (-9/2 - i9/2√3)
-33
1, 3 and 9 are the factors of 9. 3 x 3 is the prime factorization of 9. 3 + 3 + 3 are three numbers that add up to 9.
A number is divisible by 9 if all the digits add up to 9 or are a factor of. IF the digits add up to 9 (or a factor of 9), they will automatically be a factor of 3.Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
All you do is add all of the numbers 3 times and 1 an 9 4 times
7 7/12 plus 3 8/9
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