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What is another way to write P2 plus L 2 plus W?
P2 + l 2 + w
Is perimeter length plus length plus width plus width?
P=2L+2W or P= L+L+W+W In conclusion, yes it does.
The perimeter of a rectangle is 200 feet and the area is 2400 feet squared What is the length and width?
Suppose the length and width are L and W Perimeter = 2(L+W) = 200 so L+W = 100 so L= 100-W Area = L*W = 2400 so (100-W)*W = 2400 W2 - 100W + 2400 = 0 W = (100 +/- sqrt(10000 - 4*2400))/2 where the minus sign will give W and the plus sign will give L So W = (100 - sqrt(400))/2 = (100 - 20)/2 = 80/2 = 40 feet So L = 100-40 = 60 feet
What is a formula for a perimeter and area of a rectangle and of a parallelagram?
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
What is the area of a poster that has a Length equals 2 times w and Width equals w plus 2?
Stating our known facts Let W = Width, and L = Length L = 2W, and W = W+2 ----What you given is a never ending loop, saying that W always equals itself + 2. I will assume that you meant to put W = L+2 instead. Letting L = 2W and W = L + 2, we can state that x (the total area) is defined asL W(substituted so we're only working for one term)x = (2W)(2W + 2) Simplifyingx = 4W2 + 4W Since we are left with 2 variables, it can be stated that there is not enough information to solve the problem.
What is another way to write P2 plus L 2 plus W?
P2 + l 2 + w
Is the equation of perimeter for a square l plus l plus w plus w if not what is it?
That is the formula for a rectangle. In the case of a square, since length = width, this can be simplified as 4 x base, where "base" is the length of any of the 4 identical sides. In the case of a rectangle, "l+l+w+w" can be simplified to 2l + 2w, or 2(l+w).
A equals 2lw plus 2lh plus 2wh solve for h?
A = 2lw + 2lh + 2wh so A - 2lw = 2lh + 2wh = 2h(l+w) = h*2(l+w) so h = 1/2*(A-2lw)/(l+w)
Is perimeter length plus length plus width plus width?
P=2L+2W or P= L+L+W+W In conclusion, yes it does.
If a carpet has an area of 48 square meters and the perimeter is 32 square meters what is the length and width?
Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4 Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4
The perimeter of a rectangle is 200 feet and the area is 2400 feet squared What is the length and width?
Suppose the length and width are L and W Perimeter = 2(L+W) = 200 so L+W = 100 so L= 100-W Area = L*W = 2400 so (100-W)*W = 2400 W2 - 100W + 2400 = 0 W = (100 +/- sqrt(10000 - 4*2400))/2 where the minus sign will give W and the plus sign will give L So W = (100 - sqrt(400))/2 = (100 - 20)/2 = 80/2 = 40 feet So L = 100-40 = 60 feet
What is a formula for a perimeter and area of a rectangle and of a parallelagram?
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
Area formula of a rectangle?
A = Area l = length w = width A = (l)(w) Ex: L = 5 in. W = 2 in. A = ? A = l(w) A = 5(2) A = 10 in2
What is the area of a poster that has a Length equals 2 times w and Width equals w plus 2?
Stating our known facts Let W = Width, and L = Length L = 2W, and W = W+2 ----What you given is a never ending loop, saying that W always equals itself + 2. I will assume that you meant to put W = L+2 instead. Letting L = 2W and W = L + 2, we can state that x (the total area) is defined asL W(substituted so we're only working for one term)x = (2W)(2W + 2) Simplifyingx = 4W2 + 4W Since we are left with 2 variables, it can be stated that there is not enough information to solve the problem.
How do you find the area with a perimeter?
Perimeter equals 2 Length plus 2 width so find what l a w is then multiply them
What are the L plus R buttons for DEsmume?
Q=L & w=R
What is the width of a rectangle if the area is 3x2 plus 9xy plus 6y2 and the length is 3x plus 6y?
A = 3x2 + 9xy + 6y2l = 3x + 6yA = l×w∴ w = A/l∴ w = (3x2 + 9xy + 6y2) / (3x + 6y)∴ w = x + 1
