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What is the complex conjugate -6-5i?
6+5i
P and q are complex number's where p equals 2 plus 5i and q equals 6 minus i - find pq?
p = (2 + 5i)q = (6 - i)pq = (2 + 5i) (6 - i)pq = 12 + 30i - 2i - 5i2pq = 12 + 28i + 5pq = 17 + 28iIts the same as multiplying polynomials. Just multiply all the combinations of terms, group, and simplify.
Where do the parentheses go in this problem 12 plus negative 6 divided by negative five plus 2?
it would go inbetwwen 12 and negative 5i hoped this helped u /\__/\( + + )| |-----------\| \( )---------( )\ \| | | | \ \___/__| /__| \--------/\|Kitty
What plus what is -6?
Choose ANY number, for example, 5, -100, square root of 2, pi, or (5 + 3i). Subtract -6 minus your number, to get the other number.
How do you factor and equation 2X2-6X plus 9?
The best way to factor this is to use the quadratic equation. Using an equation of the form: ax2 + bx + c = 0 You use the quadratic formula like this: x = [-b +(or -) sqrt(b2-4ac)]/2a For your problem, a = 2, b = -6, and c = 9. Therefore: x = [6 +(or -) sqrt(36 - 4(2)(9))]/4 = [6 +(or -) sqrt(36-72)]/4 = [6 +(or -) sqrt(-36)]/4 = (6 +(or -)6i)/4 = 3/2 +(or -)3i/2 Therefore the factorization is (x - 3/2 - 3i/2)(x - 3/2 + 3i/2).
