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this is a very good question. lets solve (2+3i)/(4-2i). we want to make 4-2i real by multiplying it by the conjugate, or 4+2i (4-2i)(4+2i)=16-8i+8i+4=20, now we have (2+3i)/20 0r 1/10 + 3i/20 notice that -2i times 2i = -4i^2 =-4 times -1 = 4
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
if you mean both dimensions are complex numbers, then you use foil. Example (1+i)(1+2i)= 1 + 3i - 2 (since i2 = -1) -1+3i that's a rectangle but you should understand if your in a class with complex #
To add complex numbers, the real parts and the imaginary parts are added separately. For example, to add (3 + 3i) + (5 - 2i), the result is (3+5) + (3-2)i = 8+i. Subtraction is quite similar - you subtract the real and the imaginary parts separately. For example, (3 + 3i) - (5 - 2i) = (3-5) + (3 - -2)i = -2+5i.
(1+i)3 = 1 + 3i - 3 - i = -2 + 2i This is a complex number, and therefore cannot be plotted on a Cartesian plane.