2x = 5
then x*ln(2) = ln(5)
so that x = ln(5)/ln(2) = 2.3219 approx.
Wiki User
∙ 11y ago5 to the 5.23231 power
x=2*5 x=10
If 2+3 5s 5 squared is 25 then 25 times 2 equals 50
It is a quadratic equation and its solutions are: x = 3 and x = 5
It equals 0. * * * * * Unless the question is (-x)2 + (+x)2. In that case, the answer is 2x2
A similar question can be solved as below : If x to the power 4 plus 1 upon x to the power 4 equals 23 then what will be (x minus 1 upon x) to the power 2 equals what?a2 + b2 = (a + b)^2 - 2ab.so (x^2 )^2 + (1/x2)^2 = (x^2 + 1/x^2)^2 - 2 = 23.so (x^2 + 1/x^2) = 5.therefore(x - 1/x)^2 = (x^2 + 1/x^2) -2 = 5 -2 = 3.
If you mean 2a8b - 5 = x and a2b = 5, then: 2(54) - 5 = x x = 1350 - 5 x = 1345
5 to the 5.23231 power
No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.
5-x equals 7 = -2
x=2*5 x=10
x = about 1.888175023
x = 1.762340347832317
x = 3.2140958497160386
If 2+3 5s 5 squared is 25 then 25 times 2 equals 50
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.