No, to be linear, both the power of x and y need to be 1. Since x is squared, the power of x is 2.
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108
7(3y-2)-(-4y+9)
y=xsquared-4x+2
2 squared is 4 3 cubed is 27 27 plus 4 is 31
No because no 2 numbers can be squared to equal 4. 1 squared is 1 2 squared is 4 so the lowest answer is 5.
104
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
b = sqrt32 or 4 root 2
2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
It is linear.
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
y = x - 4 x^(2) + y^(2) = 8 Hence y^(2) = 8 - x^(2) Square up the linear eq'n and substitute Hence y^(2) = ( x - 4)^(2) NB Notice the RHS is wholly squared , not individual terms. Substitute ; this eliminates 'y' ( x - 4)^(2) = 8 - x^(2) Square out the brackets x^(2) - 8x + 16 = 8 - x^(2) Collect terms 2x^(2) -8x +8 = 0 Factor 2(x^(2) - 4x + 4) = 0 (x- 2)(x - 2) = 0 Hence x = 2 ( The 'x' coordinate) . Substitute into either eq;n for 'y' y = 2 - 4 y = -2 Hence ( x,y) = ( 2,-2) ; The point of contact of the tangent and the curve.
If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.