There is NO single value (THE vallue) for 2m when m takes three different values.
1/m + 1/2m = 6 LCD is 2m (2 + 1) / 2m = 6 3/2m = 6 3/6 = 2m = 1/2 m = 1/4
If: 9m+2m = 33 Then: m = 3
8 - 2m = 2 so 6 = 2m or m = 3.
-2m + 7 = m - 2 +7 +2 = m +2m 9 = 3m 3m = 9 m = 9/3 = 3 to test: -2(3) + 7 = (3) - 2 -6 + 7 = 3 - 2 1 = 1
There is NO single value (THE vallue) for 2m when m takes three different values.
2m = 26m = 26/2m = 13
1/m + 1/2m = 6 LCD is 2m (2 + 1) / 2m = 6 3/2m = 6 3/6 = 2m = 1/2 m = 1/4
If: 9m+2m = 33 Then: m = 3
8 - 2m = 2 so 6 = 2m or m = 3.
3.
-2m + 7 = m - 2 +7 +2 = m +2m 9 = 3m 3m = 9 m = 9/3 = 3 to test: -2(3) + 7 = (3) - 2 -6 + 7 = 3 - 2 1 = 1
-3m
If: -6 = 8-2m Then: m = 7
(15/m) - m + 8 = 1015/m - m = 215 - m2 - 2m = 0 or m2 +2m - 15 = 0This factoises as (m +5)( m - 3), so m = 3 or -5
2m + 5 = 10 Therefore, 2m = 5 m = 5/2 m = 2.5
0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18