Let P(x) = 2x2 - 10x + 3. Let P(x) = 0, then
2x2 - 10x + 3 = 0 (a quadratic equation, where a = 2, b = -10, and c = 3)
D = b2 - 4ac = (-10)2 - 4(2)(3) = 100 - 24 = 76
The discriminant is 900.
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
x2+10x-24 = (x-2)(x+12)
The discriminant is 900.
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
Calculate 10^2 - 4*(-16)*(-20)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
(x+1)(x+9)
x2+10x-24 = (x-2)(x+12)
(x+1)(x+9)
x2+10x+21 = (x+3)(x+7)
The browser that is used for submitting questions does not permit many mathematical symbols. It is therefore not possible to be sure what the question was. For a quadratic equation of the form ax^2 + bx + c = 0, where a, b and c are real numbers and a is non-zero, the discriminant is b^2 – 4ac.
(x - 5)(x - 5)