=> 2x + 5x = 35{collect x's}=> 7x = 35{divide both sides by 7}=> x = 35/7 = 5
2x+5x=35 what is x? x= 5 substitution ... 2x5= 10 5x5= 25 10+25= 35
2x+3x=35 5x=35 x=7
2x + 5x = 357x = 35x = 35/7x = 5
2x + 5x = 35 It is a linear equation in x so, it as only one value of x. 2x + 5x = 35 taking common x on the left side (2 + 5 )x = 35 7x = 35 dividing by 7 on both sides, we get 7x/7 = 35/ 7 X= 5 ????RIGHT????
2x + 5x = 35 7x = 35 x = 35/7 x = 5
2x + 5x = 357x = 35x = (35 / 7) = 5
2x + 5x = 35 7x = 35 divide each side by 7 x = 5
2x+5x=35 what is x? x= 5 substitution ... 2x5= 10 5x5= 25 10+25= 35
=> 2x + 5x = 35{collect x's}=> 7x = 35{divide both sides by 7}=> x = 35/7 = 5
2x+5x=35 what is x? x= 5 substitution ... 2x5= 10 5x5= 25 10+25= 35
2x+3x=35 5x=35 x=7
2x + 5x = 357x = 35x = 35/7x = 5
7
2x+5x=35 2+5(x)=35 7(x)=35 7*(5)=35 35=35
2x + 5x = 35 It is a linear equation in x so, it as only one value of x. 2x + 5x = 35 taking common x on the left side (2 + 5 )x = 35 7x = 35 dividing by 7 on both sides, we get 7x/7 = 35/ 7 X= 5 ????RIGHT????
5