2x+3y=-1 and 5x-2y=-12
3y=-2x-1 and -2y=-5x-12
y=(-2/3)x-1/3 and y=(5/2)x+6
Substitute the first value of y into the second equation
(-2/3)x-1/3=(5/2)x+6
(-19/6)x=19/3
x=-2
Plug this value of x into the first equation
2(-2)+3y=-1
-4+3y=-1
3y=3
y=1
Check your results by plugging x=-2 and y=1 into the second equation
5(-2)-2(1)=-12
-10-2=-12
-12=-12
This is correct, so the final answer is x=-2 and y=1
2x +n5y=12
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
2x+10=12 2x=2 x=1
2x-12
3x - 12 = -2x + 235x = 35 so x = 7
2x + 1 = 13; 2x = 12; x = 6
12!
2x-3=4x+9 -2x-12=0 2x=-12 x=-6
so 3x + 2 = x + 12 ie 2x = 10 x =5
2x+12-3x = 5 2x-3x = 5-12 -x = -7 x = 7
it equals 13X.
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines