For y - 2y - 3y equals 0, y equals 0.
3x + 2y = 4; 2x - 2y = 16 Add; 5x = 20 so x = 4 and y is therefore -4
2y = 15 y = 15/2 y = 7.5
3x-2y=6 -2y=-3x+6 y=1.5x-3
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
y=4
For y - 2y - 3y equals 0, y equals 0.
-2y = 10 2y = -10 y = -5
3x + 2y = 4; 2x - 2y = 16 Add; 5x = 20 so x = 4 and y is therefore -4
6x+2y=4 gives y=2-(1/3)x
x - 2y = -4 2x - y = 1 To solve this system of equations, I used matrices, and got x = 2 and y = 3.
2y = 15 y = 15/2 y = 7.5
get it to y= -2y = 1 - 2x y = x - 0.5
3x-2y=6 -2y=-3x+6 y=1.5x-3
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15
You have 2 unknowns (x,y) and only one equation, so it is unsolvable if you are trying to solve for values for x and y. However, if you are just trying to solve for x in terms of y, then the answer is x=-4+2y.