For y - 2y - 3y equals 0, y equals 0.
2y = 4 (divide both sides by 2 to solve) y = 2
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
3x-2y=6 -2y=-3x+6 y=1.5x-3
3x+2y=6 2y=-3x+6 y=-1.5x+3
-2y = 10 2y = -10 y = -5
For y - 2y - 3y equals 0, y equals 0.
80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15
2y = 4 (divide both sides by 2 to solve) y = 2
2y-3x=4
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
2y = 4x + 4y = 2x + 2
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
3x-2y=6 -2y=-3x+6 y=1.5x-3
get it to y= -2y = 1 - 2x y = x - 0.5
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2