27,68089 inch of water = 1 psi 51,715 mm of mercury = 1 psi; 742 col. Hg = 14,347 psi 742 col. Hg = 0,515 inch of water
Simple equation: ECD, ppg = [ (annular pressure, loss, psi ) ÷ (0.052 x TVD, ft) ] + (mud weight, in use, ppg)
limit is 86% of 93 psi = 86/100 x 93 psi ≈ 79.98 psi As the psi is measured to the nearest 0.1 psi, the safe limit is a measured 79.9 psi.
That's going to depend on many things you haven't mentioned, including how deep/thick you need it to be.
3113 is the symmetrical number - it reads the same backwards as it does forwards.
1419 add 3311 = 4730
The water pressure at a depth of 900 ft is approximately 390 psi.
LCM(3311, 55) = 16555
Um... there are 1 psi (lb/in2) = 144 psf (lbf/ft2) , if by (lb ft) you meant pounnds per square foot. then there is 1/144 psi in 1 (lbf/ft2)
This depends on what your target pressure is. If the height of the pipe is H in feet, the pressure at the bottom of the pipe from the column of water is 0.036127292 * H * 12 where 0.036127292 is the density of water in lbs/in^3. Thus, if your initial water pressure is I, the pressure at H feet will be I - 0.036127292 * H * 12 So you will have Height | Pressure +--------- 0 ft | 40 psi 10 ft | 35 psi 20 ft | 31 psi 30 ft | 27 psi 40 ft | 23 psi 50 ft | 18 psi 60 ft | 14 psi 70 ft | 10 psi 80 ft | 5 psi 90 ft | 1 psi 100 ft | 0 psi One will be required above 90 ft. You'll probably want one above 40 ft. Derivations: eq means equals. This wiki eats equals signs. D eq diameter of the pipe in inches, H eqheight in feet D / 2 eq R Area (A)(in^2) eq pi * R ^ 2 Volume (V)(in^3) eq A * H * 12 eq pi * R ^ 2 * H * 12 Water weight (W)(lbs) eq V * 0.036127292 eq pi * R ^ 2 * H * 12 * 0.036127292 Pressure (P)(psi) eq W / A eq V * 0.036127292 eq pi * R ^ 2 * H * 12 * 0.036127292 / pi * R ^ 2 eq H * 12 * 0.036127292
The pressure is only dependent on the height of water above the measuring point. 1 psi corresponds to a height of 2.3 ft, so 8 ft = 3.5 psi The pressure is only dependent on the height of water above the measuring point. 1 psi corresponds to a height of 2.3 ft, so 8 ft = 3.5 psi
The Solution involves the use of two basic pressure formulas, namely V= square root of 2hg where: V= discharge velocity of nozzle or muzzle (ft/sec) g= acceleration due to gravity (32 ft/sec/sec) h= velocity head (ft) An P = 0.433 h where: P- pressure head (psi) h=head(ft) Take 75 psi P= 75 psi = 0.433h h=173.2 ft V= square root of 2(32)(173.2)=105.3 ft/sec
super
10 feet x 0.433 psi/ft = 4.33 psi at the base of the cylinder.
20 ft of head can be easily converted to psi by using the specific weight of water: 62.4 lb/ft3 and converting the units to inches. 20ft * 62.4lb/ft3 / 144in2/ft2 = 8.67 psi
P = ( d H2O ) ( h H2O ) ( g / gc )P = ( 62.36 lbm/ft^3 ) ( 60 in ) ( 1 ft/ 12 in ) ( 32.17 ft/s^2 / 32.17 lbm - ft / lbf - s^2 )P = 311.8 psf
The pressure at a depth of 200 feet underwater is approximately 86.5 pounds per square inch (psi). This is because pressure increases by 0.433 psi for every foot of depth in water. So, at 200 feet deep, the pressure is 200 ft * 0.433 psi/ft = 86.5 psi.