0
Add your answer:
Earn +20 pts
What is the probability of the coin landing heads up twice and tails up once when tossed 3 times?
0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h
How do you draw a probability diagram for the number of heads coming up and how many ways they can occur from flipping three coins?
There are 8 permutations of three coins ... T T T T T H T H T T H H H T T H T H H H T H H H ... counting heads and sorting by count, you get ... 0 - T T T 1 - T T H 1 - T H T 1 - H T T 2 - T H H 2 - H T H 2 - H H T 3 - H H H ... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.
What is the number of possible outcomes when a coin is tossed twice?
4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses.
What is 4h equals 36?
4h = 36 Therefore h = 36/4 h = 9
What is 36-h equals 61?
36-h equals 61 = -25
Brain teaser 36 t in a t of h?
36 t in a t of h
What is the possible outcomes if you toss 4 coins?
1 2 3 4 h h h h h h h t h h t h h h t t h t h h h t h t h t t h h t t t t h h h t h h t t h t h t h t t t t h h t t h t t t t h t t t t
If four coins are tossed what is the probability of 2 heads 2 tails?
4 coins tossed could have the following patterns T T T T T T T H, T T H T, T H T T, H T T T T T H H, T H T H, T H H T, H H T T, H T H T, H T T H H H H T, H H T H, H T H H, T H H H H H H H Odds of 2H&2T = 6/16 = .375
Who sent messages in a balloon in the civil war?
nobody because they thought it was a piece of S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T
How many outcomes are possible if a nickel dime and quarter are flipped at one time?
8: h-h-h, h-h-t, h-t-h, t-h-h, t-t-h, t-h-t, h-t-t and t-t-t.
What is the probability of the coin landing heads up twice and tails up once when tossed 3 times?
0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h
How do you draw a probability diagram for the number of heads coming up and how many ways they can occur from flipping three coins?
There are 8 permutations of three coins ... T T T T T H T H T T H H H T T H T H H H T H H H ... counting heads and sorting by count, you get ... 0 - T T T 1 - T T H 1 - T H T 1 - H T T 2 - T H H 2 - H T H 2 - H H T 3 - H H H ... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.
What is the number of possible outcomes when a coin is tossed twice?
4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses.
If you toss a nickel a dime and a quarter what would be all the possible outcomes of his experiment?
If the 'outcome' means heads vs. tails, then there are 8 possibilities. They are: 1). H H H 2). H H T 3). H T H 4). H T T 5). T H H 6). T H T 7). T T H 8). T T T
What is 36 divided by t?
36/t
What is 4h equals 36?
4h = 36 Therefore h = 36/4 h = 9
A fish has a head 9 long The tail is equal to the size of the head plus one-half the size of the body The body is the size of the head plus the tail How long is the fish?
Step 1: Define the variables: H = Head; T = Tail; B = Body Step 2: Set up equations from what is given in the problem: H = 9 T = H + 1/2B B = H + T Total Length of the Fish = H + T + B Step 3: Substitute between equations. If we know H = 9 then we can substitute 9 in for H in the second equation. T = 9 + 1/2B Now we know what T and H are, so lets substitute that into the third equation and solve for B. B = H + T B = 9 + (9 + 1/2B) B = 18 + 1/2B Then subtract 1/2B from both sides: 1/2B = 18 Multiply both sides by two: B = 36 Now we know the value of B and the value of H. Substitute this back into the second equation and solve for T. T = H + 1/2B T = 9 + (1/2)36 T = 9 + 18 = 27 Step 4: Plug all values of H, T, and B into the final equation. Total length of fish = H + T + B Total length of fish = 9 +27 + 36 = 72
