1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P
No
Yes, providing it has 4 sides.
There are 16 possible triangles.
Sum of any two sides of a triangle is greater than third side. 3 + 4 = 7 < 8, but 7 is less than 8. So, it is not possible to form triangle with sides of length 3, 4 and 7 units.
There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
2^4 = 16
4 outcomes because you have 2 coins and you multipy that by the 2 sides 2 X 2 = 4
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
4
4
For each of the coins, in order, you have two possible outcomes so that there are 2*2*2*2 = 16 outcomes in all.
2*2*2*2 = 16
If you toss the coins once only, it is 1/4.
If each coin is a different color, then there are 32 possible outcomes. If you can't tell the difference between the coins, and you're just counting the number of heads and tails, then there are 6 possible outcomes: 5 heads 4 heads 3 heads 2 heads 1 heads all tails
It depends on the definition of an outcome. If you care about the order of the tosses, <br /> you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails).