3/7 = 1/6 = 3/42 = 1/14
6+2/4*3/3-7+6+5/3-1*1 6+1/2*1-7+6+5/3-1 6+1/2-7+6+5/3-1 =37/6 or 61/6
To convert the number ( (6 , 13)_7 ) into standard form, first note that it is in base 7. The number can be expressed as ( 6 \times 7^1 + 13 \times 7^0 ). Since ( 13 ) is not a valid digit in base 7 (valid digits are 0-6), it seems there might be a misunderstanding. If you meant ( (6 , 1 , 3)_7 ), then it would equal ( 6 \times 7^2 + 1 \times 7^1 + 3 \times 7^0 = 6 \times 49 + 1 \times 7 + 3 = 294 + 7 + 3 = 304 ) in decimal (standard) form.
4/7 * 1/6 = (4*1)/(7*6) = (2*1)/(7*3) = 2/21
6/7 x 2 1/3= 6/7 x 7/3 = 6/3 = 2
1 × 2 × 84 1 × 3 × 56 1 × 4 × 42 1 × 6 × 28 1 × 7 × 24 1 × 8 × 21 1 × 12 × 14 2 × 3 × 28 2 × 4 × 21 2 × 6 × 14 2 × 7 × 12 3 × 4 × 14 3 × 7 × 8 4 × 6 × 7
6+2/4*3/3-7+6+5/3-1*1 6+1/2*1-7+6+5/3-1 6+1/2-7+6+5/3-1 =37/6 or 61/6
2 times 3 = 6 which is less than 7 or 1 times 3 = 3 which is less than 7
7*7*2*2*5*3 =(7*7)*(2*3)*(2*5) =49*6*10 =(50-1)*6*10 =(50*6-6)*10 =(300-6)*10 =294*10 =2940
1/3 x 6/7 = 6/21 = 2/7 The reciprocal is 7/2 1/3 x 7/6 = 7/18 The reciprocal is 18/7
4/7 * 1/6 = (4*1)/(7*6) = (2*1)/(7*3) = 2/21
6/7 x 2 1/3= 6/7 x 7/3 = 6/3 = 2
1 and (1/6) = 7/6 and 1/3 * 7/6 = 7/18 Hope this helps
1 × 2 × 84 1 × 3 × 56 1 × 4 × 42 1 × 6 × 28 1 × 7 × 24 1 × 8 × 21 1 × 12 × 14 2 × 3 × 28 2 × 4 × 21 2 × 6 × 14 2 × 7 × 12 3 × 4 × 14 3 × 7 × 8 4 × 6 × 7
24
3 times 7 plus 6 is equal to 27.
The problem is 3 divided by 6/7. you can't divide a whole without putting it into a fraction, so 3 becomes 3/1, so the problem is now 3/1 divided by 6/7. to divide this, you have to multiply the reciprocal, or 7/6. so 3/1 times 7/6 equals 21/6, or 3.5 Note: You can also do 3 / 6 / 7 which would get you 14
3 5/6 x 1 7/8 is 7 3/16