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d/3+3 = 5 d+9 = 15 d = 15-9 d = 6
The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.The answer would depend on a 3-dimensional WHAT! It is not a 3-d circle, for example.
is 10*abs(d-3) or 10*|d-3| where abs is the absolute difference between d and 3 ie it is always the positive value.
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
it is where 3 and ====D connects thus, 3====D hahaha