is 10*abs(d-3) or 10*|d-3| where abs is the absolute difference between d and 3 ie it is always the positive value.
It would be: 3(7-d) as an algebraic expression
i think it might be 21.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).
A division equation with a quotient of 3 and a remainder of 15 can be expressed as ( N = 3 \times D + 15 ), where ( N ) is the dividend and ( D ) is the divisor. For example, if we let ( D = 10 ), then the equation would be ( N = 3 \times 10 + 15 = 30 + 15 = 45 ). Thus, the division equation could be ( 45 \div 10 = 3 ) with a remainder of 15.
10*abs(d - 3)
It would be: 3(7-d) as an algebraic expression
i think it might be 21.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
To find the 18th term of the arithmetic sequence 3, 10, 17, 24..., first, identify the common difference. The difference between consecutive terms is 7 (10 - 3, 17 - 10, 24 - 17). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 18th term: ( a_{18} = 3 + (18 - 1) \times 7 = 3 + 119 = 122 ).
(distance)2 = (difference in 'x' values)2 + (difference in 'y' values)2 = (3)2 + (1)2 = 10Distance = sqrt(10) = 3.1623 (rounded)
A division equation with a quotient of 3 and a remainder of 15 can be expressed as ( N = 3 \times D + 15 ), where ( N ) is the dividend and ( D ) is the divisor. For example, if we let ( D = 10 ), then the equation would be ( N = 3 \times 10 + 15 = 30 + 15 = 45 ). Thus, the division equation could be ( 45 \div 10 = 3 ) with a remainder of 15.
The sequence 3, 10, 17, 24 increases by 7 each time. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Here, ( a_1 = 3 ) and ( d = 7 ), so the nth term is ( a_n = 3 + (n-1) \times 7 = 7n - 4 ).
Circumference= D times Pi SO, the answer is 9.42
2 (x - 5) = 3 (x + 2) so 2x - 10 = 3x + 6 so x = -16. Doesn't work. Alternatively 2(5 - x) = 3 (x + 2) ie 10 - 2x = 3x + 6 ie 5x = 4 an d x = 0.8. Difference = 4.2, times 2 = 8.4 = 3 x 2.8. The number is 0.8.
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
no, d = none