It would be: 3(7-d) as an algebraic expression
i think it might be 21.
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
d / t = s30 / 3 = 10 mphd = distancet = times = speed
5.6=5.60 So it is like 5 60/100. Simplify it to 5 6/10 because 10 times 6=60 and 10 times 10=100. Simplify it again to 5 3/5. So it is 5 and 3/5. ;) :D
10*abs(d - 3)
It would be: 3(7-d) as an algebraic expression
i think it might be 21.
Apply Pythagoras. d^2 = (-6--3)^2 + ( 0 - 1)^2 d^2 = ( -3)^2 + ( -1)^(2) d^2 = 9 + 1 d^2 = 10 d = sqrt(10) = 3.1622....
Circumference= D times Pi SO, the answer is 9.42
Well, isn't that a happy little math problem! If you take 52 and divide it by 16, you'll find that it goes in 3 times with a remainder of 4. Remember, there are no mistakes in math, just happy little accidents!
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
2 (x - 5) = 3 (x + 2) so 2x - 10 = 3x + 6 so x = -16. Doesn't work. Alternatively 2(5 - x) = 3 (x + 2) ie 10 - 2x = 3x + 6 ie 5x = 4 an d x = 0.8. Difference = 4.2, times 2 = 8.4 = 3 x 2.8. The number is 0.8.
d / t = s30 / 3 = 10 mphd = distancet = times = speed
no, d = none
5.6=5.60 So it is like 5 60/100. Simplify it to 5 6/10 because 10 times 6=60 and 10 times 10=100. Simplify it again to 5 3/5. So it is 5 and 3/5. ;) :D
4D includes smell.