is 10*abs(d-3) or 10*|d-3| where abs is the absolute difference between d and 3 ie it is always the positive value.
It would be: 3(7-d) as an algebraic expression
i think it might be 21.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
d / t = s30 / 3 = 10 mphd = distancet = times = speed
10*abs(d - 3)
It would be: 3(7-d) as an algebraic expression
i think it might be 21.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
(distance)2 = (difference in 'x' values)2 + (difference in 'y' values)2 = (3)2 + (1)2 = 10Distance = sqrt(10) = 3.1623 (rounded)
Circumference= D times Pi SO, the answer is 9.42
If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10
2 (x - 5) = 3 (x + 2) so 2x - 10 = 3x + 6 so x = -16. Doesn't work. Alternatively 2(5 - x) = 3 (x + 2) ie 10 - 2x = 3x + 6 ie 5x = 4 an d x = 0.8. Difference = 4.2, times 2 = 8.4 = 3 x 2.8. The number is 0.8.
no, d = none
d / t = s30 / 3 = 10 mphd = distancet = times = speed
4D includes smell.
The difference between 3D and HD 3D is the HD, which stands for high definition. When you get to a certain number of pixels per inch, you have higher definition in your image.