The answer depends on what R and C are.
It is the same as 3 = RC which is an equation indicating an inversely proportion relation between r and c (whatever they may be).
If: C = 2r Then: r = C/2
p = r - c r - c = p r - c - r = p - r -(-c) = -(p) c = -p
p+c=r.
The answer depends on what R and C are.
It is the same as 3 = RC which is an equation indicating an inversely proportion relation between r and c (whatever they may be).
C=2(pi)(r) therefore if r equals 3.20 then C=20.1061929
If: C = 2r Then: r = C/2
p = r - c r - c = p r - c - r = p - r -(-c) = -(p) c = -p
p+c=r.
mabye
#include<stdio.h> #include<conio.h> void main() { int a[3][3],b[3][3],c[3][3],r,c; for(r=0;r<=3;r++) { for(c=0;c<3;c++) { printf("\n enter the value="); scanf("%d%d",&a[r][c],&b[r][c]); } } printf("\n first matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) { printf("%d\t",a[r][c]); } printf("\n"); } printf("\n scond matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) {printf("%d\t",b[r][c]); } printf("\n"); } printf("\n sum of given matrix=\n"); for(r=0;r<=3;r++) { for(c=0;c<3;c++) { c[r][c]=a[r][c]+b[r][c]; printf("%d\t",c[r][c]); } printf("\n"); } getch(); }
The circumference of a circle C is 2Pixr So solving for r we have C/2Pi=r
if r=5z and 15z =3 then r=10y
four a = 1 c = 3 a + c = 1 + 3 = 4
Presumably C means circumference and R means radius? If C = 2*pi*R Then R = C divided by 2*pi