If you mean 3+4b=7-2b, then you would start out with that equation I just listed. Then, you would add 2b to both sides, taking you to 3+6b=7. Then, you would subtract 3 from both sides, taking you to 6b=4. Lastly, you would divide both sides by 6, taking you to b=4/6, or 2/3. (Two-thirds)
Keep in mind that when you divide or subtract a number from both sides, the side in which it was on (ex. 4b=8), loses that number (4) and only affects THAT number. That is, on the side in which it was ON. Then, when you divide, it affects the otherside of the equation in the same way, but this time affecting any and ALL numbers and variables. In this case, the ex. would turn out to be b=2. But if it had originally been 4b=8+b, then it would turn out to be b= 2+(b/4).
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To get what is equivalent to 7 a plus 4b plus three you have to equate them to an equal sign.
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
4b + 3 = 15 First, Subtract 3 from both sides. -3 -3 4b = 12 Then, divide by 4 to get b by itself. 4 4 b = 3
3b -1
In its most simplified form: = 12abc + 8bc - 20ab = 4b(3ac + 2c - 5a) = 4b[(c + 5/3)(3a + 2) - 10/3]