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In its most simplified form:

= 12abc + 8bc - 20ab

= 4b(3ac + 2c - 5a)

= 4b[(c + 5/3)(3a + 2) - 10/3]

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Q: What is 12abc plus 8bc - 20ab?
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What is the gcf of 8a to the 2 b the 3 and 12abc?

The GCF is 4ab.


Born in 8BC dies in 23 AD how old?

30, because their was no year zero


If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?

Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11


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Related questions

What is 15a plus 20ab fully factorised?

15a + 20ab = zero5a(3 + 4b) = zerp5a=zero ............ a=zeroor3 + 4b = zero4b = -3 ............ b=-3/4


What is 20ab -8a squared?

20ab -8a squared = 12


Factor 25a squared minus 20ab plus 4b squared?

This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a


What is the gcf of 8a to the 2 b the 3 and 12abc?

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Which is the first 7 bc or 8 bc?

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What is factored form of 5a squared-20ab-25b squared?

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Express 125a3 plus 64b3 in complete factored form?

In step 4 of the special products section, the basic formula is given. It can also be found in most algebra books. (5a+4b)(25a2-20ab+16b2)


Born in 8BC dies in 23 AD how old?

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When was the first sock made?

The earliest known example is from ancient Greece, around 8BC. However, it is likely socks date back to prehistory because having wet feet is really terrible.


Who is Gaius Maecenas?

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If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?

Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11