3ab
Yes. If you have two positive integers "a" and "b", and their corresponding cubes "a^3" and "b^3" (using "^" for "power"), then the product of the two cubes would be a^3 times b^3 = (ab)^3. Since the product of "a" and "b" is also an integer, you have the cube of an integer.
Scalar product = (magnitude of 'A') times (magnitude of 'B') times (cosine of the angle between 'A' and 'B')
The commutative property of multiplication states that changing the order of the factors does not change the product. This can be represented by the equation ( a \times b = b \times a ), where ( a ) and ( b ) are any real numbers. For example, ( 3 \times 4 = 4 \times 3 ), both yielding the result of 12.
Product is 18.
The product for 3 times 9 is 27. Product is the answer you get when you multiply numbers together.
The answer to the product of a and b divided by an expression that is 3 times their difference is 3ab(a+b).
Yes. If you have two positive integers "a" and "b", and their corresponding cubes "a^3" and "b^3" (using "^" for "power"), then the product of the two cubes would be a^3 times b^3 = (ab)^3. Since the product of "a" and "b" is also an integer, you have the cube of an integer.
The product of two numbers A and B is the result of multiplying A with B. This equals adding A to itself B times. The product of 3 and 5 is 3 x 5 = 5 + 5 + 5 = 15.
Scalar product = (magnitude of 'A') times (magnitude of 'B') times (cosine of the angle between 'A' and 'B')
The commutative property of multiplication states that changing the order of the factors does not change the product. This can be represented by the equation ( a \times b = b \times a ), where ( a ) and ( b ) are any real numbers. For example, ( 3 \times 4 = 4 \times 3 ), both yielding the result of 12.
Product is 18.
the answer is81
The product for 3 times 9 is 27. Product is the answer you get when you multiply numbers together.
Hadamard product for a 3 × 3 matrix A with a 3 × 3 matrix B
A = 5 + 3*b To solve for b, rewrite as b = (A - 5) / 3
V = 1/3*B*h where B is the base area.
Given vectors A and B, the cross product C is defined as the vector that1) is perpendicular to both A and B (which is what you are looking for)2) whose magnitude is the product of the magnitudes of A and B times the sine of the angle between them.If we write the three elements of A as A(1) A(2) A(3), and the same for B, then the components of C areC(1)=A(2)*B(3)-A(3)*B(2);C(2)=A(3)*B(1)-A(1)*B(3);C(3)=A(1)*B(2)-A(2)*B(1);