3-2 + 1 = 1/ 32 + 1 = 1/9 + 1 = 1/9 + 1(9/9) = 1/9 + 9/9 = (1 + 9)/9 = 10/9 = 1 1/9 or
3-2+1 = 3-1 = 1/3
6 and 1 out of2
No say you had 3to the 2nd power + 1 to the 2nd power. u would follow order of operations and multiply first. then u would add.
10 ( x = -3)
The question is ambiguous: xa+1 * xa+1 = x2(a+1) or (xa + 1)(xa + 1) = x2a + 2xa + 1
3³ + 1³ = 27 + 1 = 28
6 and 1 out of2
2 2 -, to be exact.
No. Beta- particles, electrons, have a charge of -1, and beta+ particles, positrons, have a charge of +1.The alpha particle has a charge of +2.
1/8
No say you had 3to the 2nd power + 1 to the 2nd power. u would follow order of operations and multiply first. then u would add.
To find the number of moles of fluorine in 27 grams of oxygen difluoride (OF2), first calculate the molar mass of OF2, which is 71 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 27 grams divided by 71 g/mol equals approximately 0.38 moles of OF2. Since there are two moles of fluorine in one mole of OF2, multiply the moles of OF2 by 2 to find that there are approximately 0.76 moles of fluorine in 27 grams of OF2.
If that's 2/7 + 1/4, the answer is 15/28
10 ( x = -3)
To find the mass of sulfur hexafluoride (SF6) that has the same number of fluorine atoms as 25.0 g of oxygen difluoride (OF2), we first determine the number of fluorine atoms in OF2. Each molecule of OF2 has 2 fluorine atoms, so 25.0 g of OF2 contains 2 moles of fluorine atoms (since the molar mass of OF2 is approximately 50 g/mol). In SF6, each molecule contains 6 fluorine atoms. To match the 2 moles of fluorine atoms from OF2, we need (\frac{2}{6} = \frac{1}{3}) of a mole of SF6. The molar mass of SF6 is approximately 146 g/mol, so the mass of SF6 required is (\frac{1}{3} \times 146 \approx 48.67 , \text{g}).
The question is ambiguous: xa+1 * xa+1 = x2(a+1) or (xa + 1)(xa + 1) = x2a + 2xa + 1
3³ + 1³ = 27 + 1 = 28
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.