6 and 1 out of2
No say you had 3to the 2nd power + 1 to the 2nd power. u would follow order of operations and multiply first. then u would add.
10 ( x = -3)
3³ + 1³ = 27 + 1 = 28
The question is ambiguous: xa+1 * xa+1 = x2(a+1) or (xa + 1)(xa + 1) = x2a + 2xa + 1
6 and 1 out of2
The oxidation number of oxygen in OF2 is -1.
No. Beta- particles, electrons, have a charge of -1, and beta+ particles, positrons, have a charge of +1.The alpha particle has a charge of +2.
1/8
No say you had 3to the 2nd power + 1 to the 2nd power. u would follow order of operations and multiply first. then u would add.
To find the number of moles of fluorine in 27 grams of oxygen difluoride (OF2), first calculate the molar mass of OF2, which is 71 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 27 grams divided by 71 g/mol equals approximately 0.38 moles of OF2. Since there are two moles of fluorine in one mole of OF2, multiply the moles of OF2 by 2 to find that there are approximately 0.76 moles of fluorine in 27 grams of OF2.
If that's 2/7 + 1/4, the answer is 15/28
10 ( x = -3)
3³ + 1³ = 27 + 1 = 28
The question is ambiguous: xa+1 * xa+1 = x2(a+1) or (xa + 1)(xa + 1) = x2a + 2xa + 1
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
It is a polynomial expression in x. What about it?