If: 3x = 48 Then: x = 16
3x+1=49 49-1=48 48/3x x=16
48
3x + 13 = 61 - 3x : add 3x to both sides 6x + 13 = 61 : deduct 13 from both sides 6x = 48 : divide both sides by 6 x = 8
Let the first number be x So, x + (x+2) + [ 2 + (x +2)] = 48 x + x + 2 + 4 + x = 48 3x + 6 = 48 3x = 42 x = 14 The numbers are 14, 16 and 18
If: 3x = 48 Then: x = 16
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
the answer is 6
15-3x=48 -3x=33 x=-11
3x+1=49 49-1=48 48/3x x=16
x+ (x+1) + (x+2) = 48 3x+3 = 48 3x = 45 x = 15
48
x = 16 3x = 48 divide both sides by three to get x by itself x=16
15x2 + 58x + 48= 15x2 + 18x + 40x + 48= 3x(5x + 6) + 8(5x + 6)= (3x + 8)(5x + 6)