48
3x+1=49 49-1=48 48/3x x=16
Let the first number be x So, x + (x+2) + [ 2 + (x +2)] = 48 x + x + 2 + 4 + x = 48 3x + 6 = 48 3x = 42 x = 14 The numbers are 14, 16 and 18
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
3(x - 2)(x + 2)(x^2 + 4)
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
x+ (x+1) + (x+2) = 48 3x+3 = 48 3x = 45 x = 15
x = 16 3x = 48 divide both sides by three to get x by itself x=16
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
48
15-3x=48 -3x=33 x=-11
3x+1=49 49-1=48 48/3x x=16
x=4 or x=-4
Let the first number be x So, x + (x+2) + [ 2 + (x +2)] = 48 x + x + 2 + 4 + x = 48 3x + 6 = 48 3x = 42 x = 14 The numbers are 14, 16 and 18
Let the width be equal to x. The width is one-third the length, so the length is three times the width or 3x. The area is 48, so then 3x times x =48, or 3x squared = 48. x^2 then equals 48/3 or 16, so x =4. So the rectangle is 4 x 12 cm.
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.