If: 3x = 48
Then: x = 16
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48
3x+1=49 49-1=48 48/3x x=16
Let the first number be x So, x + (x+2) + [ 2 + (x +2)] = 48 x + x + 2 + 4 + x = 48 3x + 6 = 48 3x = 42 x = 14 The numbers are 14, 16 and 18
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
3(x - 2)(x + 2)(x^2 + 4)