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Nonreal answer if we put it into the quadratic equation 0=ax^2bx+c x=(-b[+/-](b^2-4ac)^0.5)/2a x=(7[+/-](7^2-4*3*6)^0.5)/(2*3) x=(7[+/-](49-72)^0.5)/6 x=(7[+/-]((-23)^0.5))/6 x=(7[+/-]((-23)^0.5)/6 As you cannot have the square root of a negative number (unless to take iinto account, but lets not go there) the quadratic does not cross the x-axis, so there a no real values that can be found to solve the equation (which i assume you are trying to do).
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How do you solve for c in equation 3x2 plus 17x plus c equals 0?
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
How can you solve 3x2 plus 24x equals 0?
x=-.25.
What is the answer to 7x squared plus 2x equals 0?
63828
X 2-7x plus 12 0?
The math equation of X times 2 - 7x + 12 times 0 equals 2X - 7x.
X2 plus 7x equals -2x2 plus 6?
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
What are the roots of 3x squared - 7x equals -2?
3x2 - 7x = -2 3x2 - 7x + 2 = 0 3x2 - 6x - x + 2 = 0 3x(x - 2) - 1(x - 2) = 0 (x - 2)(3x - 1) = 0 so x - 2 = 0 or 3x - 1 = 0 so x = 2 or x = 1/3
How do you solve for c in equation 3x2 plus 17x plus c equals 0?
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
Can you put the equation x2 - 5 -4x2 plus 3x equals 0 in the form ax2 plus bx plus c equals 0?
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
How can you solve 3x2 plus 24x equals 0?
x=-.25.
What is the answer to 7x squared plus 2x equals 0?
63828
X2 plus 7x plus 12 equals 0?
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
7x plus 2 equals 6x plus 2?
7x + 2 = 6x + 2 if and only x = 0.
What is 7x to the second power plus -10x plus 3 equals 0 factored?
7x2-10x+3=0 (7x-3)(x-1)=0
X 2-7x plus 12 0?
The math equation of X times 2 - 7x + 12 times 0 equals 2X - 7x.
X2 plus 7x plus 9 equals 3?
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
