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3x2 + 2x - 56 = 0

This is a quadratic equation of the form ax + by + c = 0, where a = 3, b = 2, c = -56.
Use the quadratic formula to solve the equation:

x = [-b ± √(b2 - 4ac)]/2a
x = [-2 ± √[(22 - 4(3)(-56)]]/2(3)
x = [-2 ± √(4 + 672)]/6
x = (-2 ± √676)/6
x = (-2 ± 26)/6
x = (-2 + 26)/6 or x = (-2 - 26)/6
x = 24/6 or x = -28/6
x = 4 or x = -14/3 (as a mixed number, x = - 4 2/3)

Thus, the roots of the equation are x = 4 and x = - 14/3.

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15y ago
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Q: 3x2 plus 2x minus 56
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