0
3x2 - 12 = 0
Add 12 to both sides => 3x2 = 12
Divide both sides by 3 => x2 = 4
Take square roots of both sides => x = +/- 2
Or
3x2 - 12 = 0
3(x2 - 4) = 0
3(x + 2)(x - 2) = 0
x + 2 = 0 or x - 2 = 0
x = -2 or x = 2
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What is the answer to 3x-27 equals 0?
If 3X-27= 0 then X=9
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3x + 2 = 0 3x = -2 x = -2/3
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Slope=3, y-intercept=0. y=3x or y=3x+0
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x = 0
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If 3X-27= 0 then X=9
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6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
What is the answer to 3x plus 2 equals 0?
3x + 2 = 0 3x = -2 x = -2/3
Can you put the equation x2 - 5 -4x2 plus 3x equals 0 in the form ax2 plus bx plus c equals 0?
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
What is the slope of the line y equals 3x?
Slope=3, y-intercept=0. y=3x or y=3x+0
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What is the answer to 3x -y equals 3?
0
What is the solution to 3x-3 equals -3x plus -3?
x = 0
What is the answer to negative 6x plus 9 equals 9-3x?
the answer is -3x = 0
The graph of 3x plus 4y-4 equals 0 crosses the line y equals -2 at what value of x?
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
Where do the lines 3x-y equals -4 and 3x-y equals 0 intersect?
3x - y = -4 3x - y = 0 Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other: 3x - y = -4 ∴y = 3x + 4 Now substitute: 3x - y = 0 ∴ 3x - (3x + 4) = 0 ∴ 3x - 3x - 4 = 0 ∴ -4 = 0 This result is obviously incorrect, indicating that the lines do not intersect.
What does y equal if 3x plus 6y equals 0?
y = -1x/2 3x + 6y = 0 -3x -3x __________ 6y = 0 - 3x --- -------- 6 6 y= -3x/6 y= -1x/2
