To have four numbers with a mean of 10 and a median of 10, while ensuring none of the numbers are 10, the numbers can be arranged such that two are below 10 and two are above 10. For example, a possible set of numbers could be 5, 5, 15, and 15. The mean would be (5 + 5 + 15 + 15) / 4 = 10, and the median, being the average of the two middle numbers (5 and 15), would also be 10.
It means write the next ten numbers that come after this.
The average of the first ten prime numbers is 12.9.
There are ten numbers from one to ten, if you include the one, and the ten. If you leave the one and ten out, then there are only eight numbers.
Relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.
0.01 and 100 are the only ten squared numbers.
6 is the median of 10 numbers
Yes. If the predominant data are higher than the median, the mean average will be higher than the median average. For example, the median average of the numbers one through ten is five. The mean average is five and one-half.
(1, 3, 3, 3, 5, 5, 6, 6, 8, 10)
Well, honey, to find the median of that data set, you line those numbers up in order, from smallest to biggest. Since there are 10 numbers, the median will be the average of the 5th and 6th numbers. In this case, it's 28 + 29 divided by 2, which equals 28.5. Voilà!
Here's a clue. Ten needs to be one of the numbers.
he mean of ten numbers is 58. If one of the numbers is 40, what is the mean of the other nine?
It means write the next ten numbers that come after this.
There are 4 possible answers: (7, 7, 10, 13, 13) (7, 8, 10, 12, 13) (7, 9, 10, 11, 13) (8, 8, 10, 10 14).
line up the numbers from least to greatest then start crossing off on on the right and ten one on the left and so on if you have 2 numbers in the middle you add them together and then divide by 2
{6,8,8,8,10,10,11,11,12,13} is a set of ten numbers which meets the requirements.
6 + 14
38.5