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What is the perimeter and area of an isosceles triangle with length 10 and base of length 12?
Perimeter = 10 + 10 + 12 = 32 units. Area = 48 square units
What is the perimeter and area of s equals 2.5?
If it is a square, with side (s) length 2.5 units, then perimeter = 4*s = 10 units. Area = s2 = (2.5 units)2 = 6.25 square units.
How do you find the area of a square if given a perimeter?
The perimeter of a square is the measurement of all the external sides, of which there are of course 4. We also know that for a square all of these 4 sides are of equal length. Therefore if we divide the perimeter by 4 we get the length of one side. If you then square this length (multiply it by itself) you get the area of the square. so if the perimeter measurements was 40 units 40/4 gives you the length of one side = 10 units and 10*10 gives you the area of the square - 100 square units. thus generically the area of a square with a perimeter of 'x' = (x/4)2
How do you find the area if the perimeter is only given?
If you are talking about a rectangle, you can't find the area from just the perimeter. With a perimeter of say 80 units, the sides could be 10 and 30, with an area of 300 square units. But the sides could also be 5 and 35, with an area of 175 square units. There are lots of other possibilities. If you are talking about a square, that's different. Each side is a quarter of the perimeter, so the area is a quarter of the perimeter multiplied by a quarter of the perimeter.
Right prism with a base perimeter of 10 units a height of 3 units and a total base area of 7 square units has a surface area of?
44
