4a - 5b = 7
4a +5b = 17
From the first equation:
4a = 7 + 5b
substitute this value in the second equation:
7 + 5b + 5b = 17
7 + 10b = 17
10b = 10
b = 1
Now,solve for a :
4a - 5(1) = 7
4a = 7 + 5
4a = 12
a = 3
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
It is 9
5ab-2ab+4a-b+5b = 3ab+4a+4b
The expression is: (4a+b)/(2a-5b)
8b -2a
b=7
3a - 2b
Simultaneous Equations 4a - 5b = 7 4a + 5b = 17 Add the two , this will eliminate 'b' 8a = 24 Divide both sides by '8' a = 3 When a= 3 , substitute into eityher equation for 'b'. 4(3) + 5b = 17 12 + 5b = 17 5b = 17 - 12 = 5 5b = Divide both sides by '5'. Hence 'b = 1'.
4(a+5b)
2a+6b
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)
(4, 3)