4x+3y=-15
2x-3y=-3
Take second equation and multiply the whole with 2 so that when subtracting the two equations we can cancel out x. so it becomes 4x-6y=-6
4x +3y = -15
( - ) 4x -6y = -6
----------------------------------
0x + (+3-(-6))y = -15 - (-6))
9y = -9 .. or y=-1
So take any one equation and find x by substituting y value
2x - 3(-1)= -3
2x +3 = -3
2x = -6
x = -3
So x = -3, y = -1
yes
(1) x+y=15(2) 4x+3y=38From (1) one gets x=15 -y, put into(2)4(15-y)+3y=3860-4y+3y=3860-y=38y=22 then x=15-y=-7(-7,22) is the solution
That depends on what the value of x is.
-2x plus 3y equals 1
2x-11
4.34684352143
Put the equation in this form: y=mx+b. Then m will be the slope. 2x3y+6=0 2x3y=-6 3y=-6/2x y=-2/2x y=-1/x This equation does not describe a straight line, but rather, it describes a curve.
yes
80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15
OK, so-3y + 15 - y = 39-3y + 15 - 15 - y = 39 - 15-3y -y = 24-4y = 24-y = 6y= -6.Hope this helps!
(2,7)
3y+5=y-25 2y=-30 y= -15
5x+3y
(1) x+y=15(2) 4x+3y=38From (1) one gets x=15 -y, put into(2)4(15-y)+3y=3860-4y+3y=3860-y=38y=22 then x=15-y=-7(-7,22) is the solution
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
That depends on what the value of x is.
-2x plus 3y equals 1