4 x 58 = 232
21 x 4 = 84
58 x 34 = 1972 5/8 x 3/4 = 15/32
x = 6 So y = 9*6 + 4 = 54 + 4 = 58 The ordered pair is (6, 58)
x/4 + 5 = -1 (4)x/4 +(4)5 = -1 x+20 = -1 -20 -20 x= -21 x= -21
4 x 58 = 232
4.7 x 58 4 x 58 = 232 .7 x 58 = 40.6 add these together and the answer is 272.6
The first ten positive integer multiples of 58 are: 1 x 58 = 58 2 x 58 = 116 3 x 58 = 174 4 x 58 = 232 5 x 58 = 290 6 x 58 = 348 7 x 58 = 406 8 x 58 = 464 9 x 58 = 522 10 x 58 = 580
58/75 = 58/75 x 100 % = 58 x 100/75 % = 58 x 4/3 % = 232/3 % ≈ 77.33 %
21 x 4 = 84
58 x 34 = 1972 5/8 x 3/4 = 15/32
1 x 232, 2 x 116, 4 x 58, 8 x 29, 29 x 8, 58 x 4, 116 x 2, 232 x 1.
Suppose the two numbers are x and y. Then x + y = 58 and x - y = 16 The second equation gives x = 16 + y Substituting this value of x into the first equation gives (16 + y) + y = 58 or 2y + 16 = 58 or 2y = 42 which gives y = 21. Then x = 16 + y gives x = 16 + 21 = 37 So the soln is x = 37, y = 21
1 x 116, 2 x 58, 4 x 29.
21 x 4 = 84
x = 6 So y = 9*6 + 4 = 54 + 4 = 58 The ordered pair is (6, 58)
Prime Factorization of 58 Using ExponentsThe prime factorizatio of 58 is:2 X 29Exponents are not needed because only one 2 and one 29 are the prime factors of 58. If exponents were used, it would be 21 X 291.