Suppose the two numbers are x and y.
Then x + y = 58 and x - y = 16
The second equation gives x = 16 + y
Substituting this value of x into the first equation gives
(16 + y) + y = 58
or 2y + 16 = 58 or 2y = 42 which gives y = 21.
Then x = 16 + y gives x = 16 + 21 = 37
So the soln is x = 37, y = 21
204
Numerical equations have only numbers and symbols, while algebraic equations have variables also.
I think you have mistyped your question...
x + y = 23x - y = 7Add the equations:2x = 30x = 15Subtract the equations:2y = 16y = 8
You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.
It is a trivial difference. If you multiply every term in the equation with rational numbers by the common multiple of all the rational numbers then you will have an equation with integers.
204
Numerical equations have only numbers and symbols, while algebraic equations have variables also.
6
Exponential and logarithmic functions are different in so far as each is interchangeable with the other depending on how the numbers in a problem are expressed. It is simple to translate exponential equations into logarithmic functions with the aid of certain principles.
To find two numbers that equal a sum of 7 and a difference of 1, let’s denote the numbers as ( x ) and ( y ). From the information given, we can set up the equations: ( x + y = 7 ) and ( x - y = 1 ). Solving these equations, we find that ( x = 4 ) and ( y = 3 ). Thus, the two numbers are 4 and 3.
I think you have mistyped your question...
x + y = 23x - y = 7Add the equations:2x = 30x = 15Subtract the equations:2y = 16y = 8
Let the two numbers be ( x ) and ( y ). From the information given, we can set up the equations: ( x - y = 10 ) and ( x + y = 14 ). Solving these equations, we find that ( x = 12 ) and ( y = 2 ). Thus, the two numbers are 12 and 2.
You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.
Let the two numbers be m and n From the information given, we have two equation in two unknowns. We can solve this system using substitution. Here are the two equations. m+n=92 m-n=20 Now to use substitution, we must rewrite the second equation as m=n+20 and substitute it into the first n+n+20=92 or 2n=72 which tells us n=36 that means m=92-36 or 56. So the numbers are 36 and 56. Let's check 36+56=92 56-36=20
Let X be one number and Y the other. So, X + Y = 8 and X - Y = 12 Solve the set of equations simultaneously or use substitution method. X + Y = 8 X - Y = 12 (ADD THIS EQUATION TO FIRST ONE) _______________ 2X = 20, So X =10 and solving for Y using either equation, Y = -2