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5 (a) Given that h(x)=x2-16/x-2(2 marks)(in) the valves of × for which h(x) = 0. (3 m)?
Updated: 10/17/2024
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Earn +20 ptsQ: 5 (a) Given that h(x)=x2-16/x-2(2 marks)(in) the valves of × for which h(x) = 0. (3 m)?
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How do you form a straight line equation given only the points of k 3h and 3k h?
With difficulty if you don't know the methods and one of the methods is as follows:- Let the points (k, 3h) and (3k, h) be (x1, y1) and (x2, y2) respectively: (y-y1) over (y2-y1) = (x-x1) over (x2-x1) (y-3h) over (h-3h) = (x-k) over (3k-k) (y-3h) over (-2h)) = (x-k) over (2k) Multiply both sides by -2hk to eliminate the fractions: k(y-3h) = -h(x-k) ky-3hk = -hx+hk ky = -hx+hk+3hk ky = -hx+4hk The above straight line equation can be expressed as: hx+ky-4hk = 0
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What is the straight line equation in its general form connected by the end points of k 3h and 3k h on the Cartesian plane showing work?
Points: (k, 3h) and (3k, h) Slope: h-3h/3k-k = -2h/2k => -h/k Equation: y-3h = -h/k(x-k) => ky-3hk = -h(x-k) => ky = -hx+hk+3hk Equation in its general form: hx+ky-4hk = 0
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