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Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
The distance between points x1 y1 and 5 -5 is the square root of x1 plus 5 2 plus y1 - 52?
false
How Do You Solve Y2-5Y plus 4 equals 0?
Y²-5Y+4=0 Y1=-(-5/2) - Square root of ((-5/2)²-4) Y1= 2.5 - Square root of 2.25 Y1 = 1 Y2=-(-5/2) + Square root of ((-5/2)²-4) Y2= 2.5 + Square root of 2.25 Y2 = 4 Y can be either 1 or 4
How do you graph the equation y equals x plus 2 on a TI-84 Plus calculator?
Press the Y= button and type 'X+2' (not the quotes) next to Y1 (or any other Y will work). Then press GRAPH. (To type X, press the X,T,θ,n button. If you don't see Y1= when you press Y=, press MODE and select FUNC, then try again.)
3 solutions to y equals -4x - 5?
X , y1 , -92 , -133 , -17
Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
The distance between points x1 y1 and 5 -5 is the square root of x1 plus 5 2 plus y1 - 52?
false
How do you solve 3x-y1 9x-3y equals -3?
It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
What is the formula to calculate the slope?
It's m = y2 - y1/ x2- x1 It's m equals y2 minus y1 over x2 minus x1
How Do You Solve Y2-5Y plus 4 equals 0?
Y²-5Y+4=0 Y1=-(-5/2) - Square root of ((-5/2)²-4) Y1= 2.5 - Square root of 2.25 Y1 = 1 Y2=-(-5/2) + Square root of ((-5/2)²-4) Y2= 2.5 + Square root of 2.25 Y2 = 4 Y can be either 1 or 4
What is the y intercept of this line 2x y1?
Unfortunately, limitations of the browser that is used by WA means that most symbols cannot be seen. Please resubmit using words like "plus", "minus" and "equals".
The distance between points (x1 y1) and (4 8) is the square root of (x1 - 8)2 plus (y1 - 4)2.?
It is false-apex
X1 plus x2 divided by 2 y1 plus y2 divided by 2?
formula for the midpoint of a line
How do you graph the equation y equals x plus 2 on a TI-84 Plus calculator?
Press the Y= button and type 'X+2' (not the quotes) next to Y1 (or any other Y will work). Then press GRAPH. (To type X, press the X,T,θ,n button. If you don't see Y1= when you press Y=, press MODE and select FUNC, then try again.)
3 solutions to y equals -4x - 5?
X , y1 , -92 , -133 , -17
What does m equal in y equals mx plus b?
m is the slope of the line; that is, the change in y divided by the change in x
M is the midpoint of pq verify that this is the midpoint by using the distance formula to show tha pm equals mq?
Let P(x1, y1), Q(x2, y2), and M(x3, y3).If M is the midpoint of PQ, then,(x3, y3) = [(x1 + x2)/2, (y1 + y2)/2]We need to verify that,√[[(x1 + x2)/2 - x1]^2 + [(y1 + y2)/2 - y1]^2] = √[[x2 - (x1 + x2)/2]^2 + [y2 - (y1 + y2)/2]^2]]Let's work separately in both sides. Left side:√[[(x1 + x2)/2 - x1]^2 + [(y1 + y2)/2 - y1]^2]= √[[(x1/2 + x2/2)]^2 - (2)(x1)[(x1/2 + x2/2)) + x1^2] + [(y1/2 + y2/2)]^2 - (2)(y1)[(y1/2 + y2/2)] + y1^2]]= √[[(x1)^2]/4 + [(x1)(x2)]/2 + [(x2)^2]/4 - (x1)^2 - (x1)(x2) + (x1)^2 +[(y1)^2]/4 + [(y1)(y2)]/2 + [(y2)^2]/4 - (y1)^2 - (y1)(y2) + (y1)^2]]= √[[(x1)^2]/4 - [(x1)(x2)]/2 + [(x2)^2]/4 + [(y1)^2]/4 - [(y1)(y2)]/2 + [(y2)^2]/4]]Right side:√[[x2 - (x1 + x2)/2]^2 + [y2 - (y1 + y2)/2]^2]]= √[[(x2)^2 - (2)(x2)[(x1/2 + x2/2)] + [(x1/2 + x2/2)]^2 + [(y2)^2 - (2)(y2)[(y1/2 + y2/2)] + [(y1/2 + y2/2)]^2]]= √[[(x2)^2 - (x1)(x2) - (x2)^2 + [(x1)^2]/4 + [(x1)(x2)]/2 + [(x2)^2]/4 + (y2)^2 - (y1)[(y2) - (y2)^2 + [(y1)^2]/4) + [(y1)(y2)]/2 + [(y2)^2]/4]]= √[[(x1)^2]/4 - [(x1)(x2)]/2 + [(x2)^2]/4 + [(y1)^2]/4 - [(y1)(y2)]/2 + [(y2)^2]/4]]Since the left and right sides are equals, the identity is true. Thus, the length of PM equals the length of MQ. As the result, M is the midpoint of PQ
