false
No.
You take the square root of X( subpoint 2) minus x subpoint 1 plus y 2 minus y1
the distance formula for coordinates is : d=square root of ( 2nd x coordinate minus 1st x coordinate)squared plus(2nd y coordinate minus 1st y coordinate) squared sorry if it's a little confusing
Find the average of the two sides (Longest length plus shortest length. Divide this addition by 2). Multiply the result by its height (which is the distance between the longest side and the shortest side).
6a square plus b square
There are none. Those two curves do not intersect.
The distance between two points is: square root of [(x1-x2)^2 plus (y1-y2)^2] An exact answer could have been given if the points were properly enumerated.
It is false-apex
You take the square root of X( subpoint 2) minus x subpoint 1 plus y 2 minus y1
the distance formula for coordinates is : d=square root of ( 2nd x coordinate minus 1st x coordinate)squared plus(2nd y coordinate minus 1st y coordinate) squared sorry if it's a little confusing
The word is worth 11 points, plus and bonus square scores.
You use the Pythagorean theorem. Specifically, the distance is the square root of ((difference in x-coordinates) squared + (difference in y-coordinates) squared).
AA is worth 2 points in Scrabble, plus any bonus square points. If you make the word on a triple-word square, it will be worth 6 points.
You can find that using the distance formula, but in order to accomplish that, you need coordinate points, not equations. To get order points, you find the value of y in each equation when you substitute the same thing for x: y=(2/7)x+4 y=(2/7)x-2 Plug in x=0, for example, but you can actually plug in anything you want. y=(2/7)(0)+4 y=(2/7)(0)-2 ;Plug in 0 for x in each equation y=0+4 y=0-2 ;Multiply (2/7) and 0, and anything times 0 is 0 y=4 when x=0 y=-2 when x=0 (0,4) (0,-2) There are your coordinates. Now we can plug them in into the distance formula. The distance 'd' between the points A=(x1, y1) and B=(x2, y2) is given by the formula: d=square root of [(x2-x1)2+(y2-y1)2] Your points A and B are (0,4) and (0,-2). Plug them into the formula: d=square root of [(0-0)2+(-2-4)2] d=square root of [(0)2+(-6)2] d=square root of [0+36] ;Square root of 36 is 6 d=6 The distance between the two lines is 6 units.
the distance between epicentre plus its focal point( the exact point where earthquake occured, i.e. depth) is hypocentral distance.
2000 plus km
Just like the gravitational force between masses, the electrostatic force between two charges is inversely proportional to the square of the distance between them. When the distance between the charges is changed from 3cm to 6cm, the distance changes by the factor of (6/3) = 2. The force changes by the factor of ( 1/22 ) = 1/4. Its magnitude changes to 0.25 that of the original force.
For two coordinates points (x1, y1) and x2, y2), you can find the straight line distance using the Pythagorean theorem.The vertical difference (y1-y2) forms one side of the triangle, and the horizontal difference is the other (x2-x1). The hypotenuse is the straight distance along the line, and is defined by :h = square root of (a2 plus b2) = square root of [ (y2-y1)2 + (x2-x1)2 ]---EXAMPLE :For points (1, 3) and (4, 7), the distance along y is (7-3) and along x is (4-1) andsquare root [ 42 + 32 ] = sq rt [9 + 16] = sq rt [25] = 5.Measuring the distance along the line would verify that the distance is 5.