It is not opssible to give a sensible answer to this question. 46+58 = 104. So if the class has 46% girls and 58% boys then the class has 4% who are simultaneously girls and boys.
80 boys and 30 girls
80 = 100% 8 = 10% 32 = 40% 80 - 32 = 48
%*amount=answer .40*45=answer answer=18 boys
18 boys 30 girls
There are 8 boys and 12 girls and 8 students with glasses.
60%
40%
Suppose there are b boys in the school. Then there are 2*b girls. So there are 2b + b = 3b girls and boys 3b = 1500 so b = 500 and then 2b = 1000 So there are 500 boys and 1000 girls.
It is not opssible to give a sensible answer to this question. 46+58 = 104. So if the class has 46% girls and 58% boys then the class has 4% who are simultaneously girls and boys.
Boys make up 40% of the class (12 boys out of 30 total students).
80 boys and 30 girls
80 = 100% 8 = 10% 32 = 40% 80 - 32 = 48
%*amount=answer .40*45=answer answer=18 boys
If there are 24 girls in a class of 50 and we assume the remaining students are boys, then there are 26 boys and the ratio of boys to girls is 26boys/24girls = 13/12=1.08333 boys for each girl.
18 boys and 12 girls
Well, isn't that a happy little math problem! If the ratio of girls to boys is 5 to 4, that means for every 5 girls, there are 4 boys. To find out how many girls in a class of 108 students, we first need to divide 108 by the total parts in the ratio (5+4=9), which is 12. Then, we multiply 108 by the girls' share (5/9) to find there are 60 girls in the class.