(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
C = 25 + (10 x 4) = 25 + 40 = 65
5/c
The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
5 °C - 10 °C = -5 °C (i.e. 5 degrees Celsius below 0 °C or 5 °C below freezing)
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
C = 25 + (10 x 4) = 25 + 40 = 65
5/c
The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
5 °C - 10 °C = -5 °C (i.e. 5 degrees Celsius below 0 °C or 5 °C below freezing)
5 c of pastries
-3
C2 + 10C + 25 The expression is a perfect square, so both factors are the same. (C + 5) and (C + 5)
-15+c+5 = 75 c = 75+15-5 c = 85
It depends on the value of c. If c = 0 then 0-0+5 = 5 If c = 1 then 1-2+5 = 4 If c = 2 then 4-4+5 = 5 and so on.
5 - c = 3 c = 5 - 3 Therefore, c = 2
Just substitute the "c" with 4 and the "a" with negative 5, as c=4 and a=-5. So the equation is 4-(-5) which is simply 4+5. And the rest you should be able to do from there.