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(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
5/c
The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
5 c of pastries
5 °C - 10 °C = -5 °C (i.e. 5 degrees Celsius below 0 °C or 5 °C below freezing)