10x2 +4x + 21 = 0=> 4*x +10*x^2 +21 = 0Complex roots:Root 1: -0.2-1.435 * iRoot 2: -0.2+1.435 * i
(5x - 4)(2x + 7)
(5x - 4)(2x + 3)
x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x - 6)(x - 4).
1/4
10x2 +4x + 21 = 0=> 4*x +10*x^2 +21 = 0Complex roots:Root 1: -0.2-1.435 * iRoot 2: -0.2+1.435 * i
10x2 - 64 = 36 + 6x2 Combine like terms: 4x2 = 100 Divide both sides by 4: x2 = 25 Take square roots: x = -5 or +5
(5x - 4)(2x + 7)
Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.
(5x - 4)(2x + 3)
x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x - 6)(x - 4).
x(x + 4)(x + 6)
1/4
x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x2 - 4x - 6x + 24) = x[ x(x - 4) - 6(x - 4) ] = x(x - 6)(x - 4)
Yes: the equation is tautological!
How about 32 + 1 - 4 ?
8