No.
Can you Graph: x4 +10x2 + 33x2 + 38x +8 Find: All X-Intercepts, Y-Intercept, Turning points
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
28 is.
yes
Not necessarily.
Given: x4 + 3x3 - 10x2 = 0 You can start by dividing both sides of the equation by x2: x2 + 3x - 10 = 0 Then factor out the left side of the equation into simpler terms: (x + 5)(x - 2) = 0 For the result to be 0, either of the terms in brackets on the left must equal 0, so that means there are two answers: x = -5, x = 2
No.
Can you Graph: x4 +10x2 + 33x2 + 38x +8 Find: All X-Intercepts, Y-Intercept, Turning points
4X + 2x = 1. Where x = 0.166666666666666666666666666666666666666 recurring.
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
28 is.
7
yes
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
If there is a remainder then it's not a factor otherwise yes
Yes.