Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
5x2-2x+16=4x2+6x ,or x2-8x+16=0, or x2-2(x)(4)+(4)2=0, or (x-4)2=0, or (x-4)(x-4)=0, or x=4
5y2 + 5x2 = 1 Substitute y = 2x + 1 into this equation: 5*(2x + 1)2 + 5x2 = 1 5*(4x2 + 4x + 1) + 5x2 - 1 = 0 25x2 + 20x + 4 = 0 which factorises to (5x + 2)2 = 0 Therefore x = -2/5 And then y = 2x + 1 gives y = 1/5 So the two points of intersection are coincident, at (-2/5, 1/5)
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
5x2-2x+16=4x2+6x ,or x2-8x+16=0, or x2-2(x)(4)+(4)2=0, or (x-4)2=0, or (x-4)(x-4)=0, or x=4
x = 2 or x = 2/5
5x2-2x = 0 x(5x-2) = 0 Therefore: x = 0 or x = 2/5
5y2 + 5x2 = 1 Substitute y = 2x + 1 into this equation: 5*(2x + 1)2 + 5x2 = 1 5*(4x2 + 4x + 1) + 5x2 - 1 = 0 25x2 + 20x + 4 = 0 which factorises to (5x + 2)2 = 0 Therefore x = -2/5 And then y = 2x + 1 gives y = 1/5 So the two points of intersection are coincident, at (-2/5, 1/5)
5x2 - 20 = 0x2 - 4 = 0x2 = 4x = +2 and -2
False
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
The sum of 2 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 equals 2.
It equals 6
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
5x2+500 = 844.45 5x2 = 844.45-500 5x2 = 344.45 x2 = 344.45/5 x2 = 68.89 x = the square root of 68.89 = 8.3 x = 8.3